Calculate the percentage of ionic character for HF having bond length 0.83A and dipole moment 1.82D

Calculate the percentage of ionic character for HF having bond length

1.	Calculate the percentage of ionic character for HF having bond length 0.83A and dipole moment 1.82D
Answer» \xa0To calculate % gornic character we consider 100 % iconic bond.μ=Q×d=(1.60×10−19C)×0.83×10−10m×(1D/ 3.336×10−30\u200b)% gonic character\xa0=1.82/3.980 \u200b×100=45.70%% covalent character = (100-% ginoc character)=54.3%