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Calculate the percentage of nitrogen and oxygen in ammonium nitrate. [Relative molecular mass of ammonium nitrate is 80, [H = 1, N = 14, O = 16] |
Answer» Ammonium nitrate = NH4NO3 Relative mol. wt. = 14 + 1 x 4 + 14 + 3 x 16 = 80 Total nitrogen in ammonium nitrate = 14 + 14 Percentage of nitrogen = \(\frac{28}{80}\times 100\) = 35% Total oxygen in ammonium nitrate = 16 x 3 Percentage of oxygen = \(\frac{48}{80}\times100\) = 60% |
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