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| 1. |
Calculate the percentage of nitrogen in urea (NH2CONH2) |
| Answer» The formula of urea is NH2CONH2Molar mass = 60.01 g/molAtomic mass of N = 14 and\xa0Number of atoms = 2That means, 14 {tex}\\times{/tex} 2= 28g/mol of ureaMW urea = 60.1%N = 100% x 28.0 g N / 60.1 g urea = 46.66 %NOr\xa0%N= 28/60{tex}\\times{/tex}100= 46.66 % N | |