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Calculate the pH at \(\cfrac{M}{1000}\) sodium hydroxide solution assuming complete ionisation (Kw = 1 x 10-14). |
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Answer» NaOH monobasic so that, normality = molarity \(\therefore\) concentration of NaOH = concentration of \(\bar O\)H [\(\bar O\)H] = [NaOH] = \(\cfrac{M}{1000}\) = 0.001 M = 0.001 M POH = - log[\(\bar O\)H] = - log 0.001 = - log 10-4 = 4 log 10 POH = 4 We know that PH + POH = 14 PH = 14 - POH = 14 - 4 PH = 10 Hence, PH at \(\cfrac{M}{1000}\) sodium hydroxide solution will be 10 |
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