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Calculate the pH at which `Mg(OH)_(2)` begins to precipitate from a solution containing 0.10 M `Mg^(2+)` ions. `K_(sp)` of Mg`(OH)_(2)=1xx10^(-11)`. |
Answer» Minimum `[OH^(-)]` after which `Mg (OH)_(2)` begins to precipitate can be calculated from `[Mg^(2+)][OH^(-)]^(2)=K_(sp) ` of `Mg(OH)_(2)` `(0.10)[OH^(-)]^(2) = 10^(-11) or [OH^(-)]^(2) = 10^(-10) or [OH^(-)]=10^(-5) or [H^(+)]=10^(-9) or pH = 9` |
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