Calculate the pH of 0.001 M aqueous solution of ZnCl_2, K_a for the equilibrium, Zn^(2+)+H_(2) O hArrZn (OH)^(+)+H^(+)is1 xx 10^(-9)

Calculate the pH of 0.001 M aqueous solution of ZnCl_2, K_a for the eq

1.	Calculate the pH of 0.001 M aqueous solution of ZnCl_2, K_a for the equilibrium, Zn^(2+)+H_(2) O hArrZn (OH)^(+)+H^(+)is1 xx 10^(-9)
Answer» Solution : `[H^(+)] = C XX h = c sqrt(K_H // C)= sqrt(K_H xxC ) = sqrt(10^(-9) xx 0.001 ) = 10^(-6)` `pH =- log [10^(-6) ]=6`