Calculate the pH of 0.001 Maniline. What is the ionisation constant of anilinium cation? (K_b= 3.5 xx10^(-10))

Calculate the pH of 0.001 Maniline. What is the ionisation constant of

1.	Calculate the pH of 0.001 Maniline. What is the ionisation constant of anilinium cation? (K_b= 3.5 xx10^(-10))
Answer» SOLUTION :`[OH^(-) ]=sqrt(K_b C ) = sqrt( 3.5xx 10^(-10 ) xx 10^(-3)) = 6 xx 10^(-7) mol L^(-1)` `pOH = -log 6 xx 10^(-7)= 7-log 6` pH = 14 - 7 + log 6 = 7.78 IONISATION constant of anilinium cation is the RATIO of `K_w and K_b` `k_a = (K_w)/(k_b) = ( 1 xx 10^(-14) )/(3.5 xx 10^(-10)) = 2.86 xx 10^(-5)`