1.

Calculate the pH of 0.05 M NaOH solution.

Answer»

[OH] = 0.05 = 5 ×10–2

pOH = – log[OH]

= – log (5 × 10–2) = – 0.699 + 2

= 1.3010 pH = 14 – pOH

= 14 – 1.3010 = 12.699



Discussion

No Comment Found

Related InterviewSolutions