

InterviewSolution
Saved Bookmarks
1. |
Calculate the pH of 0.05 M NaOH solution. |
Answer» [OH–] = 0.05 = 5 ×10–2 pOH = – log[OH–] = – log (5 × 10–2) = – 0.699 + 2 = 1.3010 pH = 14 – pOH = 14 – 1.3010 = 12.699 |
|