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Calculate the pH of 0.10 M solution of `Nh_(4)Cl.` The dissociation constant `(K_(b))` of `NH_(3)` is `1.8xx10^(-5)` |
Answer» `NH_(4)Cl` is a salt of strong acid and weak base. `pH=7-1/2[pK_(b)+logc]` `=7-1/2[-log(1.8xx10^(-5))+log0.10]` `=7-1/2(5-0.26-1)=5.12` |
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