1.

Calculate the pH of 0.125M H2SO4.

Answer»

H2SO4→ 2H+ +SO42-

[H+] = 2[H2SO4

= 2 × 0.125 

= 0.25

pH = -log10[H+

= -log10[0.25] 

= -log10 [2.5 × 10-1]

pH = -log2.5 - log10-1 

= -0.3979 + 1 

= 0.6021.



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