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Calculate the pH of 0.125M H2SO4. |
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Answer» H2SO4→ 2H+ +SO42- [H+] = 2[H2SO4] = 2 × 0.125 = 0.25 pH = -log10[H+] = -log10[0.25] = -log10 [2.5 × 10-1] pH = -log2.5 - log10-1 = -0.3979 + 1 = 0.6021. |
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