1.

Calculate the ph of 1.00×10^-4 molar solution of HNO3​

Answer»

Answer:

\displaystyle \sf \longrightarrow 5 \\

Explanation:

Given :

\displaystyle \sf Concentration [ \ H^+ \ ] = 1.00\times10^{-4} \ M \\ \\

We are asked to FIND pH :

We know :

\displaystyle \sf pH=-\log [ \ H^+ \ ] \\ \\

PUTTING VALUES here we get :

\displaystyle \sf pH=-\log [ \ 1.00\times10^{-4} \ ] \\ \\

\displaystyle \sf pH=-\log [ \ 10.0\times10^{-5} \ ] \\ \\

Using log RULE :

\displaystyle \sf \longrightarrow \log a^x=x. \log a \\ \\

\displaystyle \sf \longrightarrow \log 10=1 \\ \\

\displaystyle \sf \longrightarrow pH=-(-5).\log [ \ 10.0 \ ] \\ \\

\displaystyle \sf \longrightarrow pH=5.\log [ \ 10.0 \ ] \\ \\

\displaystyle \sf \longrightarrow pH=5\times1 \\ \\

\displaystyle \sf \longrightarrow pH=5 \\ \\

Hence we get REQUIRED answer!



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