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Calculate the pH of 10^(-10) M NaOH solution. |
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Answer» Solution :`[OH^(-)]` from NaOH `=10^(-10)M, [OH^(-)]` from ` H_(2)O=10^(-7)M` total `[OH^(-)]=10^(-10)+10^(-7)=10^(-7)(10^(-3)+1)=1.001xx10^(-7)M` `:. pOH = - log (1.001xx10^(-7))=7-log 1.001=7-0.0004=6.9986` or `pH = 14 - 6.9996 = 7.0004` |
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