1.

Calculate the pH of `10^(-10)` M NaOH solution.

Answer» `[OH^(-)] " given by base " = 10^(-10) M`
`[OH^(-)] " given by water "=10^(-7) M`
`" Total "[OH^(-)] =10^(-10) M+ 10^(-7) M= 10^(-7) (10^(-3)+1) = 1.001 xx 10^(-7) M`
`pOH =- log (1.001 xx 10^(-7)) = (7 - log 1.001)`
`=7 -0.0004 = 6.9996 , pH =14 -6.9996 = 7.0004`


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