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Calculate the pH of `10^(-10)` M NaOH solution. |
Answer» `[OH^(-)] " given by base " = 10^(-10) M` `[OH^(-)] " given by water "=10^(-7) M` `" Total "[OH^(-)] =10^(-10) M+ 10^(-7) M= 10^(-7) (10^(-3)+1) = 1.001 xx 10^(-7) M` `pOH =- log (1.001 xx 10^(-7)) = (7 - log 1.001)` `=7 -0.0004 = 6.9996 , pH =14 -6.9996 = 7.0004` |
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