InterviewSolution
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InterviewSolution
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) Calculate the pH of 108 M aqueous solution of HCI (log1.1=0.12). |
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Answer» Since it is very dilute acidic solution, so H+concentrations from acid and water are comparable, and the concentration of H+from water cannot be neglected. Therefore,[H+]total= [H+]acid+ [H+]waterSince HCl is a strong acid and is completely ionized[H+]HCl= 1.0 x 10-8The concentration of H+from ionization is equal to the [OH-] from water,[H+]H2O= [OH-]H2O= x (assume)[H+]total= 1.0 x 10-8+ xBut[H+] [OH-] = 1.0 x 10-14(1.0 x 10-8+ x) (x) = 1.0 x 10-14X2+ 10-8x – 10-14= 0Solving for x, we get x = 9.5 x 10-8Therefore,[H+] = 1.0 x 10-8+ 9.5 x 10-8= 10.5 x 10-8= 1.05 x 10-7pH = – log [H+] = – log (1.05 x 10-7) = 6.98 |
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