Calculate the pH of a buffer solution obtained by mixing 1.5 mole of s

1.	Calculate the pH of a buffer solution obtained by mixing 1.5 mole of sodium acetate and 0.09 mole of CH3COOH.{Ka = 1.8 × 10-5 }.
Answer» From Henderson equation of acidic buffer solution we know, pH = pKa +log [A^-]/[salt] degree of ionization (∞) = √Kc/C = 3.4e-3 So,[CH₃COO^-] = C∞ = 3.4e-3 × 0.09 = 0.306e-3 So, pH = 4.7 + log [ 0.306e-3]/1.5 = 4.7 + log 0.0204 (log 0.0204 = -1.69) = 4.7 - 1.69 = 3.01

Calculate the pH of a buffer solution obtained by mixing 1.5 mole of sodium acetate and 0.09 mole of CH3COOH.{Ka = 1.8 × 10-5 }.

Answer»

From Henderson equation of acidic buffer solution we know,

pH = pKa +log [A^-]/[salt]

degree of ionization (∞) = √Kc/C = 3.4e-3

So,[CH₃COO^-] = C∞ = 3.4e-3 × 0.09 = 0.306e-3

So, pH = 4.7 + log [ 0.306e-3]/1.5 = 4.7 + log 0.0204 (log 0.0204 = -1.69)

= 4.7 - 1.69

= 3.01

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Calculate the pH of a buffer solution obtained by mixing 1.5 mole of sodium acetate and 0.09 mole of CH3​​​​​COOH.{Ka = 1.8 × 10-5 }.

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Calculate the pH of a buffer solution obtained by mixing 1.5 mole of sodium acetate and 0.09 mole of CH3COOH.{Ka = 1.8 × 10-5 }.