Calculate the pH of a solution obtained by diluting 25 ml of N/100 HCl

1.	Calculate the pH of a solution obtained by diluting 25 ml of N/100 HCl to 500 ml.
Answer» SOLUTION :`N_(1)V_(1)=N_(2)V_(2), :. 25xx1//100=N_(2)xx500 or N_(2)=5xx10^(-4)N` `[H^(+)]=[HCL] = 5xx10^(-4)M` `pH = - LOG (5xx10^(-4))=4-log 5 = 4 - 0.6990 = 3.301`.

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