1.

Calculate the pH of acid with Ka = 10^-6 and 0.01 M 0 4 6 2 ?? Give detailed answer pls

Answer»

PH=8Explanation:PH=1/2 [PKa-log(ACID)]PH=1/2 [6-log(0.01)]PH=1/2(6-(-2))=1/2(8)=4Therefore,PH=8.



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