Calculate the pH of N/1000 sodium hydroxide solution assuming complete

1.	Calculate the pH of N/1000 sodium hydroxide solution assuming complete ionization (K_(w)=1.0xx10^(-14))
Answer» Solution :NaOH completely IONIZES as : `NaOH rarr Na^(+) + OH^(-)` `:. [OH^(-)]=[NaOH]=(N)/(1000)=10^(-3)N=10^(-3)M ` (`:'` Eq. mass = Mol. Mass in case of NaOH) Now, as `[H_(3)O^(+)][OH^(-)]=10^(-14) :. [H_(3)O^(+)]=(10^(-14))/([OH^(-)])=(10^(-14))/(10^(-3))=10^(-11)` `:. PH = - log [H_(3)O^(+)]= - log 10^(-11) =11`

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