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Calculate the pH of one molar ammonium formate solution. Given that pK_a for HCOOH = 3.8,PK_b for NH_3 = 4.8. |
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Answer» Solution :HYDROLYSIS of AMMONIUM acetate is given by the equation as `HCOONH_4 +H_2O hArr HCOOH +NH_4 OH` PH of the solution of a salt of weak ACID and weak base `=1/2[pK_w+PK_a-PK_b ]` pH of 1M `HCOONH_4` solution`= 1/2 (14+3.8-4.8) = 6.5`. |
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