Calculate the pH of the resultant mixtures : 10 mL 0.01 M H_2SO_4 + 10 mL 0.01 M Ca(OH)_2

Calculate the pH of the resultant mixtures : 10 mL 0.01 M H_2SO_4 + 1

1.	Calculate the pH of the resultant mixtures : 10 mL 0.01 M H_2SO_4 + 10 mL 0.01 M Ca(OH)_2
Answer» SOLUTION :10 mL 0.01 M `H_2SO_4 = (10xx0.01)` =0.1 millimol `H_2SO_4` 10 mL 0.01 M `Ca(OH)_2=(10xx0.01)` = 0.1 millimol `Ca(OH)_2` Total volume 20 ml = `20/1000` L = 0.02 L NeutralisationReaction : `{:(Ca(OH)_2 +,H_2SO_4 to , CaSO_4 + , 2H_2O),("1 MOL", "1 mol" , " 1 mol" , "2 mol") :}` 0.1 m mol + 0.1 m mol `to` 0.1 m mol Thus, `H_2SO_4` and `Ca(OH)_2` COMPLETE neutralise mixture remain neutral. `therefore` pH=7.0