Calculate the pH of the solution obtained by mixing 100 cm^(3) of solution with pH = 3with 400 cm^(3) of solution with pH = 4 .

Calculate the pH of the solution obtained by mixing 100 cm^(3) of solu

1.	Calculate the pH of the solution obtained by mixing 100 cm^(3) of solution with pH = 3with 400 cm^(3) of solution with pH = 4 .
Answer» Solution :`100 cm^(3) ` of solution with PH = 3 CONTAINS `H^(+)=(10^(-3))/(1000)xx100=10^(-4)`mole `400cm^(3) ` of solution with pH = 4 contains `H^(+)=(10^(_4))/(1000)xx400=4XX10^(-5) ` mole TOTAL `H^(+)=10^(-4)+4xx10^(-5)=10^(-4)(1+0.4)=1.4xx10^(4)`. Total volume = `500 cm^(3)` `:. [H^(+)]=(1.4xx10^(-4))/(500) xx1000M = 2.8xx10^(-4)M` `pH = - log (2.8xx10^(-4))=4-0.4472 ~~ 3.55`