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Calculate the pH value of 0.0001 M `HNO_(3)` |
Answer» Correct Answer - `pH =4` `HNO_(3)` is a strong acid and it dissociates completely in aqueous solution. The concentration of the ions is the same as that of the acid `HNO_(3) overset((aq))(to) underset(0.0001 M)(H_(3)O^(+)) +underset(0.0001M)(NO_(3)^(-)(aq))` `[H_(3)O^(+)] =0.0001 M =10^(-4) M` `pH =- log [H_(3)O^(+)] =-log [10^(-4)] =(-) (-4) log 10=4` |
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