Calculate the POH of 0.005M HCL solution.

1.	Calculate the POH of 0.005M HCL solution.
Answer» <STRONG>Answer: HCl is a strong ACID that dissociates COMPLETELY: HCl(aq) → H+(aq) + Cl-(aq) [H+] = [HCl] = 0.005M PH = -LOG [H+] pH = - log 0.005 pH = 2.3

Answer»

<STRONG>Answer:

HCl is a strong ACID that dissociates COMPLETELY:

HCl(aq) → H+(aq) + Cl-(aq)

[H+] = [HCl] = 0.005M

PH = -LOG [H+]

pH = - log 0.005

pH = 2.3

Discussion