Calculate the pOH of a solution obtained when 0.05 mol NH_(4)Cl is added and dissolved in 0.025 M ammonia solution. Kb for ammonia is 1.77xx10^(-5)

Calculate the pOH of a solution obtained when 0.05 mol NH_(4)Cl is add

1.	Calculate the pOH of a solution obtained when 0.05 mol NH_(4)Cl is added and dissolved in 0.025 M ammonia solution. Kb for ammonia is 1.77xx10^(-5)
Answer» SOLUTION :`pKb=log[KB]` `=log[1.77xx10^(-3)]` `=5-0.2480=4.752` `pOH=pK_(b)+log=(["salt"])/(["BASE"])=4.752+"log"([0.05])/([0.025])` `=4.752+log2=4.752+0.3010=5.053`