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Calculate the `pOH` of solution at `25^(@)C` that contains `1xx10^(-10) M` of hydronium ions, i.e., `H_(3)O^(+)`A. `1.000`B. `7.000`C. `4.000`D. `9.000` |
Answer» Correct Answer - C `C_(H_(3)O^(+))=10^(-pH) mol L^(-1)` `=10^(-10)mol L^(-1)` `:. pH = 10` Now, for any aqueous solution at `25^(@)C`, `pH+pOH=14` `:. pOH=14-pH` `=14-10` `=4` |
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