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Calculate the potential difference between points B and D of the network of resistance shown in figure |
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Answer» Here, potential differences across ABC = potential differences across ADC = 12 V Current in arm ABC, `I_(1)=12/6+4 =1.2A` pot. Diff. between A and B, `V_(A) - V_(B)=I_(1) xx 6 =1.2 xx 6=7.2 V` Current in arm ADC, `I_(2)=12/8+12=0.6A` pot. diff. across A and D, `V_(A) - V_(D) = I_(2) xx 8 = 0.6 xx 8 =4.8 V` `:. (V_(A) - V_(B)) - (V_(A) - V_(D))= 7.2 - 4.8 = 2.4 V` or `V_(D) - V_(B) = 2.4 V` `:. V_(B) - V_(A)= -2.4 V` It shows that the point D is at higher potential than that of point B. |
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