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Calculate the power of an engine which can pull a mass of 500 metric ton up an incline rising I in 100 with a velocity of 10ms^(-1). |
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Answer» Solution :`SINTHETA=(1)/(100).Vm//s,m=500xx10^(3)KG` `F=mg sin theta=500xx10^(3)xx9.8xx(1)/(100)=49xx10^(3)N` power `P=FV=49 xx 10^(3)xx10=49xx10^(4)` walt = 490 KW |
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