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Calculate the power of an engine which can pull a mass of 500metric ton up an incline rising 1 in 100 with a velocity of 10 ms^(-1) |
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Answer» Solution :`SIN theta = (1)/(100), V= 10 m//s, m= 500 xx 10^(3)KG` `F= mg sin theta = 500 xx 10^(3) xx 9.8 xx (1)/(100) = 49 xx 10^(3)N` Power `P= FV = 49 xx 10^(3) xx 10= 49 xx 10^(4)` watt = 490 KW |
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