1.

Calculate the pressure exerted by 0.250 moles of carbon dioxide in 0.275 litres at 100^@C and compare this value with that expected for an ideal gas. (Given : a = 3.59 L^2 " atm " mol^(-2), b = 0.0427 L mol^(-1))

Answer»


Solution :For n moles of a gas, van der Waals. EQUATION can be written as
`(P+(an^2)/V_2)(V - nb) = nRT`
Substituting the corresponding values, we have
`[P+(3.59 xx (0.250)^2)/((0.275)^2)][0.275 - (0.250 xx 0.0427)]`
`= 0.250 xx 0.0821 xx 373`
which gives, P = 26 atm.
Under similar conditions, for an IDEAL gas
`P=(nRT)/V = (0.250 xx 0.0821 xx 375)/(0.275) =27.8` atm,
Hence, the PRESSURE exerted by `CO_2` under given conditions is 26 atm. An ideal gas, under similar conditions will EXERT a pressure of 27.8 atm.


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