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Calculate the pressure exerted by `8.5 g` of ammonia `(NH_(3))` contained in a `0.5 L` vessel at `300 K`. For ammonia, `a=4.0 atm L^(2)mol^(-2)`, `b=0.036 L mol^(-1)`. |
Answer» Number of moles of ammonia `n=(8.5)/(17)=0.5 mol` According to van der Waals equation `(P+(an^(2))/V^(2))(V-nb)=nRT` `P=(nRT)/((V-nb))-(an^(2))/(V^(2))=(0.5xx0.082xx300)/((0.5-0.5xx0.036))-(4(0.5)^(2))/((0.5)^(2))` `=21.51 atm` |
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