1.

Calculate the pressure exerted by one mole of CO2 gas at273 K if the van der Waals' constant a = 3.592 dmo atmmol . Assume that the volume occupied by CO2molecules is negligible.62(2000)

Answer»

van der Waal’s equation for one mole of a gas is

[P + a/V²] (V - b) = RT ….(1)

Give that volume occupied by CO2molecules, ‘b’ = 0

Hence, (1) becomes [P + a/V²] V = RT or P = RT/V – a/V²

Using R = 0.082 , T = 273K, V = 22.4 l for 1 mole of an ideal gas at 1 atm pressure.

Case I. 1 * V = 12/m R (t + 273) ….(1)

Case I. 1 * V = 12/m R (t + 273) ….(1)

∴ P = 0.082 *273/22.4 – 3.592/(22.4)⁴=0.9922 atm



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