1.

Calculate the pressure in the following cases : (i)On the surface ofa block , if it weighs 60 N and is lying on a side with area 0.3 m x 0.1 m. (ii)On the same 60 N block , if it is lying on a side with area 0.1 m x 0.2 m .

Answer»

Solution :i. Pressure =Force/AREA
=60 N / (0.3 m x 0.1 m)
=`60 N // (0.03 m^2)`= 2000 Pa
II. Pressure = Force/Area
=60 N / (0.1 m x 0.2 m)
`=60//0.02 m^2`= 3000 Pa
Therefore , we notice that for the same force , pressure INCREASES as area DECREASES .


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