Calculate the pressure of `10^(23)` molecules of sulphur dioxide `(SO_(2))` when enclosed in a vessel of `2.5 L` capacity at a temperature of `27^(2)C`.

Calculate the pressure of `10^(23)` molecules of sulphur dioxide `(SO_

1.	Calculate the pressure of `10^(23)` molecules of sulphur dioxide `(SO_(2))` when enclosed in a vessel of `2.5 L` capacity at a temperature of `27^(2)C`.
Answer» Correct Answer - `1.653 xx 10^(-1) atm` According to ideal gas equation : `PV = nRT` , or `P = (nRT)/(V)` `n = (1 xx 10^(22))/(N_(O)) = (1 xx 10^(22))/(6.022 xx 10^(23)) = 1.66 xx 10^(-2) mol, V = 2.5 L` `R = 0.083 L "bar" K^(-1) mol^(-1), T = 27 + 273 = 300 K` `P = ((1.66 xx 10^(-2) mol) xx (0.083 L "bar" K^(-1) mol^(-1)) xx (300 K))/((2.5 L)) = 1.653 xx 10^(-1)` atm

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Calculate the pressure of `10^(23)` molecules of sulphur dioxide `(SO_(2))` when enclosed in a vessel of `2.5 L` capacity at a temperature of `27^(2)C`.

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