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Calculate the rate at which water flows through a capillary tube of length 0.5m with an internal radius of 1mm. Coefficient of viscosity is 1.3xx10^(-3)kg//m-s. The pressure head is 20 cm of water. |
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Answer» Solution :From Poiseuille.s formula `V=(piPr^(4))/(8etal)` `=(3.14xx20xx10^(-2)xx1000xx9.8xx(10^(-3))^(4))/(8xx1.3xx10^(-3)xx0.5)=7.4xx10^(-8)m^(3)s^(-1)`. |
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