1.

Calculate the rate of flow of heat through a metal sheet 0.02 m thick and area 50 xx 10^(-4) "m"^(2) with its two sides at 273 K and 293 K respectively. Given K=0.2 cal cm""^(-1) "s"^(-1) "c"^(-1).

Answer»


Solution :`Q//t = KA ( theta_1 - theta_2) // x = (0.2 XX 4.2 xx 10^(2) ) xx 50 xx 10^(-4) xx 20//0.02 = 420 "Js"^(-1)`


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