1.

Calculate the ratio of number of pure and hybrid orbitals used for bonding in an acetylene molecule

Answer»

Solution :ACETYLENE has TWO C atoms and two H atoms. Carbon undergoes sp hybridisation.
Number of hybrid orbitals `=2xx2=4`
Number of PURE orbitals =4 (from C) +2 (from H)=6
Ratio of number of pure and hybrid orbitals `=4:6=2:3`


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