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Calculate the ratio of number of pure and hybrid orbitals used for bonding in an acetylene molecule |
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Answer» Solution :ACETYLENE has TWO C atoms and two H atoms. Carbon undergoes sp hybridisation. Number of hybrid orbitals `=2xx2=4` Number of PURE orbitals =4 (from C) +2 (from H)=6 Ratio of number of pure and hybrid orbitals `=4:6=2:3` |
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