Calculate the ratio of solubility of AgCl " at "25 ^(@) Cin 3.0 M NH_3 (K_(sp)of AgCl in NH_3 " is "3.1 xx 10^(-3) ) and " in "H_2O (K_(sp)of AgCl in H_2O" is"1.8 xx 10^(-10)) .If answer is 1.15 xx 10 ^(x)then x=________?

Calculate the ratio of solubility of AgCl " at "25 ^(@) Cin 3.0 M NH_3

1.	Calculate the ratio of solubility of AgCl " at "25 ^(@) Cin 3.0 M NH_3 (K_(sp)of AgCl in NH_3 " is "3.1 xx 10^(-3) ) and " in "H_2O (K_(sp)of AgCl in H_2O" is"1.8 xx 10^(-10)) .If answer is 1.15 xx 10 ^(x)then x=________?
Answer» Solution :` AgCl + 2NH_3 hArr [Af(NH_3)_2 ]^(+)+CL^(-), K_1` ` ((X)/(3-2x) )^(2) K_1 RARR (x) /( 3-2x) =sqrt( K_1) ~~(x)/(3) ` `AgCl hArr Ag^(+)+Cl^(-),K_2` ` (x)/(y)=sqrt(( K_1)/(K_2)) xx 3 =sqrt((3.1xx 10^(-3))/(1.8 xx 10^(-10))) xx 3 =1.2 xx 10^(4) `