1.

Calculate the relative rates of diffusion of""^235UF_6 and ""^238UF_6in gaseous form (F= 19).

Answer»


Solution :ACCORDING to Graham.s law of diffusion,
`r_1/r_1 = sqrt(d_2/d_1) = sqrt(M_2/M_1)`
The molecular weight of `""235UF_6 = 235 + (6 XX 19) = 349 (M_1)`
The molecular weight of `""238UF_6 = 238 + (6 xx 19) = 352 (M_2)`
`:. "" r_1/r_2 = sqrt(352/349)= 1.0043/1`
HENCE, the rates of diffusion of`""^235UF_6 and ""^238UF_6 " are in the ratio " 1.0043 : 1`.


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