1.

Calculate the resistivity of the material of a wire 1.0 m long, 0.4 mm diameter and having a resistance of `2.0 Omega`.

Answer» Correct Answer - ` 2.53 xx 10^(-6) Omega m`
`rho = (RA)/(l) = (R pi D^(2))/(4l) = (2.0 xx 3.142 xx (0.4 xx 10^(-3))^(2))/( 4xx 10)`
`= 2.51 xx 10^(-8) Omega m`


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