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Calculate the resistivity of the material of a wire `1.0 m` long, `0.4 mm` in diameter and having a resistance of `2.0 Omega`. |
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Answer» Correct Answer - `25 xx 10^-8 ohm m` As `R = (rho l)/(A) = (rho l)/(pi r^2), rho = (pi R r^2)/(l)=(3.14 xx (2.0 Omega) xx (0.2 xx 10^-3 m)^2)/(1.0 m) =25 xx 10^-8 Omega m`. |
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