1.

Calculate the resonance energy of N2O from the following data: Δf H0 of N2O =82 KJ mol-1 , Bond energies of NΞN, N=N,O=O and N=O bonds are 946 ,418 ,498 and 607 kj mol-1 respectively.

Answer»

The equation for the formation of one mole of N2O will be 

 NΞN (g) + ½ O=O (g) ---> N=N=O 

Calculated value of ΔfH0 for this reaction will be ΔfH0 = [B.E.(NΞN) + ½ B.E.(O=O)] – [B.E.(N=N) + B.E.(N=O)] 

 =[946 + ½ (498)] – [418 + 607] kj mol-1 = 170kj mol-1 

Resonance energy = Observed ΔfH0 – Calculated ΔfH0 = 82 – 170 = - 88 kj mol-1



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