1.

Calculate the rms velocity of oxygen molecules at S.T.P. The molecular weight of oxygen is 32.

Answer» Here, `P=1 atm = 1.013 xx 10^(5) N//m^(2)`
`M= 32 g = 32 xx 10^(-3) kg`
V = molar volume at STP
`= 22.4 litre = 22.4 xx 10^(-3) m^(3)`
`C_(rms) =?`
`C_(rms) = sqrt((3RT)/(M))= sqrt((3PV)/(M))`
`= sqrt((3 xx 1.013 xx 10^(5) xx 22.4 xx 10^(-3))/(32 xx 10^(-3)))`
`= 461.23 m//s`.


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