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Calculate the root mean square speed of smoking practices of mass 5xx10^(-17) kg in their Brownian motion in air at S.T.P |
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Answer» Solution :Given `K = 1.38xx10^(-23) ` J/K Here, `m = 5 xx10^(-17) KG, k = 1.38xx10^(-23)J//K` `T = 0^@C=(0+273)K=273K,v_(rms)=? ` `v_(rms)=SQRT((3RT)/M)=sqrt((3kNT)/(mN))` `=sqrt((3KT)/m)` `sqrt((3xx1.38xx10^(-23)xx273)/(5xx10^(-17)))` `v_(rms)=1.5xx10^(-2)m//s=1.5cm//s` |
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