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| 1. |
Calculate the self inductance of a solenoid having 500 turns about a cylindrical core of 2 cm radius in which µr = 50 for 0 < rho < 0.5 cm. |
| Answer» <html><body><p><strong>Answer:</strong></p><p>The self-inductance is given as,</p><p></p><p><a href="https://interviewquestions.tuteehub.com/tag/l-535906" style="font-weight:bold;" target="_blank" title="Click to know more about L">L</a>= </p><p>l</p><p>μ </p><p>0</p><p> </p><p> N </p><p>2</p><p> A</p><p> </p><p> </p><p></p><p>= </p><p>50×10 </p><p>−2</p><p> </p><p>4π×10 </p><p>−7</p><p> ×(<a href="https://interviewquestions.tuteehub.com/tag/500-323288" style="font-weight:bold;" target="_blank" title="Click to know more about 500">500</a>) </p><p>2</p><p> ×π×(2×10 </p><p>−2</p><p> ) </p><p>2</p><p> </p><p> </p><p> </p><p></p><p>=7.896×10 </p><p>−4</p><p> H</p><p></p><p>Thus, the self-inductance of an air <a href="https://interviewquestions.tuteehub.com/tag/solenoid-1216573" style="font-weight:bold;" target="_blank" title="Click to know more about SOLENOID">SOLENOID</a> is 7.896×10 </p><p>−4</p><p> H.</p><p></p><p></p><p><strong>Explanation:</strong></p><p>please mark as brainlist </p></body></html> | |