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InterviewSolution
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Calculate the shortest wavelength of light emitted in the Paschen series of hydrogen spectrum. Which part of the electromagnetic spectrum, does it belong ? ( Given : Rydberg constant , R = `1.1 xx 10^(7)m^(-1)` |
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Answer» The wave number of the spectral lines forming Paschen series is given by `vec(v)=1/lambda=R(1/3^(2)-1/n_(i)^(2)).n_(i)=4,5,6,...` The shortest wavelength of the spectral lines (series limit) of Paschen series is given by `1/(lambda Pa_(min)) =R(1/3^(2)-1/(oo^(2)))= R//9 rArr lambda Pa_min=9/R` `9//_1.1xx 10^(7)=8199A^(@)` The series lies in infrared region of em spectrum. |
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