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Calculate the sides of PQRS. |
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Answer» PQ = \(\sqrt{(7-5)^2+(8-7)^2}\) = \(\sqrt{2^2+1^2}\) = \(\sqrt{5}\) QR = \(\sqrt{(5-5)^2+(9-8)^2}\) = \(\sqrt{(-2)^2+1^2}\) = \(\sqrt{5}\) RS = \(\sqrt{(3-5)^2+(8-9)^2}\) = \(\sqrt{(-2)^2+(1)^2}\) = \(\sqrt{5}\) SP = \(\sqrt{(5-3)^2+(7-8)^2}\) = \(\sqrt{2^2+1^2}\) = \(\sqrt{5}\) |
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