1.

Calculate the sides of PQRS.

Answer»

PQ = \(\sqrt{(7-5)^2+(8-7)^2}\) = \(\sqrt{2^2+1^2}\) = \(\sqrt{5}\)

QR = \(\sqrt{(5-5)^2+(9-8)^2}\) = \(\sqrt{(-2)^2+1^2}\) = \(\sqrt{5}\)

RS = \(\sqrt{(3-5)^2+(8-9)^2}\) = \(\sqrt{(-2)^2+(1)^2}\) = \(\sqrt{5}\)

SP = \(\sqrt{(5-3)^2+(7-8)^2}\) = \(\sqrt{2^2+1^2}\) = \(\sqrt{5}\)



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