1.

Calculate the solubility of A_(2)X_(3) in pure water, assuming that neither kind of ion reacts with water. The solubility product of A_(2)X_(3), K_(sp)=1.1xx10^(-23).

Answer»


Solution :`{:(A_(2)X_(3),hArr,2A^(3+),+,3X^(2-),,,),(s,,s,,s,,,):}`
`:. K_(sp)=(2S)^(2)(3s)^(3) = 108 s^(5)`
`s=(K_(AP)/108)^(1//5)=(1.1xx10^(-23)//108)^(1//5)`
`log s = (1)/(5)(log 1.1 + log 10^(-23)-log 108 ) = (1)/(5) (0.0414-23-2.0334)`
or `log s = - 4.9984 = bar(5) .0016 :. s= 10^(-5) "mol" L^(-1)`


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