Calculate the solubility of A_2X_3 in pure water , assuming that neither kind of ion reacts with water. The solubility product of A_2X_3 , K_(sp)=1.1xx10^(-23).

Calculate the solubility of A_2X_3 in pure water , assuming that neith

1.	Calculate the solubility of A_2X_3 in pure water , assuming that neither kind of ion reacts with water. The solubility product of A_2X_3 , K_(sp)=1.1xx10^(-23).
Answer» Solution :Suppose , S mol `L^(-1)` is soluble in sparingly soluble salt of concentrated solution of `A_2X_3`. The following IONIC equilibrium of this concentrated solution. `{:(A_2X_(3(s)) to ,2A_((aq))^(3+)+, 3X_((aq))^(2-)),("Conc. according to stoichiometry:","2S M","3S M"):}` `therefore K_(SP)=[A^(3+)]^2 + [X^(2-)]^3 =(2S)^2 (3S)^3` `therefore K_(sp) =108 S^5 =1.1xx10^(-23)` `therefore 108 S^5 =111.0 xx 10^(-25)` `therefore S=(111xx10^(-25))^(1/5) =2.5645xx10^(-5)` M `approx 2.56xx 10^(-5)` M Here, `(111xx10^(-25))^(1/5) =1/5 LOG (111xx10^(-25))` `=1/5 log 111 + 1/5 log 10^(-25)` `=1/5 (2.0453)+1/5(-25)` =0.4090 + (-5) Antilog of `=2.5645xx10^(-5)`