1.

Calculate the solubility of CaF_(2) in water at 298 K which is 70% dissociated. K_(sp) of CaF_(2) is 1.7 xx 10^(-10). If answer is x xx 10^(-4) mol/ltr thenx = ____?

Answer»


Solution :`CaF_2 hArr underset( 0.75)(CA^(+2) ) +underset( 1.4s)(2F^(-))`
` 1.7 XX 10^(-10)=(0.7S) (1.4S) ^(2) `
` 1.7xx 10^(-10)=1.4 xx S^(3) rArr S= 5 xx 10 ^(_4) `


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