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Calculate the solubility of CaF_(2) in water at 298 K which is 70% dissociated. K_(sp) of CaF_(2) is 1.7 xx 10^(-10). If answer is x xx 10^(-4) mol/ltr thenx = ____? |
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Answer» ` 1.7 XX 10^(-10)=(0.7S) (1.4S) ^(2) ` ` 1.7xx 10^(-10)=1.4 xx S^(3) rArr S= 5 xx 10 ^(_4) ` |
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