InterviewSolution
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InterviewSolution
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Calculate the solubility of `CoS` in `0.1M H_(2)S` and `0.15M H_(3)O^(oplus) (K_(sp)` of `CoS = 3 xx 10^(-26))`. `(K_(1) xx K_(2) (H_(2)S) = 10^(-21))` |
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Answer» a. `H_(2)O +H_(2)S overset(K_(1))hArrH_(3)O^(oplus) +HS^(Θ)` `H_(2)O +HS^(Θ) overset(K_(2))hArrH_(3)O^(oplus) +S^(2-)` `K_(1)K_(2) = ([H_(3)O^(oplus)]^(2)[S^(2-)])/([H_(2)S])=10^(-21)` In `0.1M H_(2)S` and `0.15M H_(3)O^(oplus)` `[S^(2-)] = ((0.15)^(2)[S^(2-)])/(0.1) = 10^(-21)` `:. [S^(2-)] = (10^(-22))/(0.0225) = 4 xx 10^(-21)` `K_(sp) = [Co^(2+)] [S^(2-)] = 3 xx 10^(-26)` `[Co^(2+)] = (3xx10^(-26))/(4xx10^(-21)) = 7 xx 10^(-6)M` |
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